ns am currently taking a basic dearteassociazione.org course and during a lab they had actually us carry out the following procedure:

Place $pu2 mL$ the $5\%$ $ ceNaClO $ equipment in a test tube.Add $10$ autumn of cyclohexane.Add ~$10$ autumn $pu6 M,ceHCl$In an additional test tube, add a pinch of heavy $ceKBr$Use a dropping pipette to retract the chlorine/cyclohexane great from above and include it come the test tube containing $ceKBr$

When ns did this, the mixture turned dark red and bubbled with a hints of violet to it. In my lab report, mine teacher desires me to create the net ionic equation(s) of this reaction, however I have actually no idea exactly how to do that.

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How would you proceed?


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Safdar Faisal
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I"d favor to add some things to what Tanith Rosenbaun said.

First, the point of net ionic equations is not simply to write out the equations in regards to ions, but to focus on just those ion that suffer a change in charge or valence. Ions which don"t change in charge don"t really participate in the reaction and called spectator ions.

Here"s the last equation indigenous Rosenbaum"s answer:

$$ce2H3O+ + 2Cl- + 2Na+ + CO3^2- -> 2H2O + 2Cl- + 2Na+ + CO2$$

Notice the the sodium and chloride ions are unchanged in this reaction. So us drop them, and just write out the ions that change:

$$ce2H3O+ + CO3^2- -> 2H2O + CO2$$

This is the net ionic equation: it focuses exactly on what is interesting, i beg your pardon in this case is the neutralization reaction.

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Now let"s go ago to your problem: human being have been asking what you know about it. You seem to know that you room transferring a solution of chlorine liquified in cyclohexane. You gained that chlorine native the adhering to reaction:

$$ce2HCl + NaClO -> Cl2 + NaCl + H2O$$

and the chlorine preferentially dissolves in the cyclohexane. Now it"s crucial to understand that the cyclohexane doesn"t pat any role in the second part of her experiment, it"s just exactly how you move the chlorine. (And it"s why you should be cautious with acids approximately bleach: chlorine gas is poisonous!)

The crucial question is: what happens as soon as you put elemental chlorine in the visibility of liquified potassium bromide?

$ceCl2 + KBr -> ?$ (Note: this is not balanced yet!)

In particular, do you know what you created when that systems turned dark red? Hint: this is a an extremely important property that halogens prefer chlorine and also bromine have actually towards every other, i m sorry is without doubt seen finest via a network ionic equation. I"ll happily carry out the price if you"ve tried part stuff and also are still stuck.