We retained arguing, but I really couldn"t prove that we need much more than 2 currently on letter "W" to create 6 triangles except that ns couldn"t discover a method of law so. Is there any proof because that this kind of problem?
PS. Sorry. Ns didn"t clarify. Girlfriend CANNOT combine one or an ext triangles to kind a triangle and count that separately. Triangles must be within disjoint.For instance, if triangle ABC, BCD have the right to be an unified to form triangle ADC, then us don"t count ADC together a triangle.
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No one stated the W couldn"t be "cursive"...
It just takes two lines to obtain six triangles? allow me shot to add a photo real quick.
So much the max i can find with 2 lines is $5$. Ill save trying!
Consider this 2 lines / but a bit more inclined and one intersecting each other. Currently the suggest where lock cross needs to be in among the main side in W. Sorry because that no having a picture.
Three parallel currently one in ~ the top, one middle, one bottom, and, if tri inside tri is allowed, you have $6$. Of these, $3$ room true and $3$ an ext are built approximately their particular parent.
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count the number of triangles inside $3-4-5-$triangle
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