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Let x equal the the smallest of the 4 numbers. Therefore:
Therefore the four odd numbers are 7, 9, 11, and 13. Since all space prime except 9, 3 of the numbers are prime.
The positive integer
We recognize that the remainder,
Let"s look in ~ a little example, the numbers in between 1 and also 3 consisting of all endpoints. We have actually 1, 2, and also 3. If we subtract our numbers, we gain 2. We require to add one more to gain all the preferred numbers. We deserve to follow the same process with our bigger numbers.
Then, including 1,
Therefore, our answer is
Mrs. Lovell assigns she reading class to review pages three through sixty-four of your textbook. How many pages must each college student read?
To counting the variety of pages in in between these two web page numbers, we want to subtract
Therefore, ours answer is
An important consideration whenever you"re asked because that the variety of integers in between two various other numbers is to determine whether the two "end points" room included. Right here the indigenous "inclusive" tells united state that we need to count both -8 and 17 in our calculation.
A advantageous tip for these questions: if you"re including both finish points, you have the right to calculate by using the variety (greatest worth minus smallest value) and adding 1 come account for the inclusive set. (If you have to prove the to yourself, just use "how many integers between 1 and 3 inclusive" - clearly the set is 1, 2, 3 for three integers, yet 3-1 = 2, therefore you have the right to see you need to include one much more to acquire the answer).
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For this question, that pipeline us v 17 - (8) = 25 together the range, and if you include 1 to the for "inclusive" you obtain the exactly answer, 26.
Another method to look in ~ this one is to chop the up: between -8 and 17 there space 8 negative integers (-1 v -8), 17 positive integers (1 through 17), and 0 as one more integer. 8 + 17 + 1 = 26.