I assumed that checking the solubility would be a good idea since of the presence of an alcohol yet will I notice a difference due to the fact that the alcohol has 8 carbon atoms. And they all react with bromine water, $\ceKMnO4$ and $\ceH2SO4$. I think I"m lacking something.
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Alkene is finest characterized, then, through its propertyof decolorizing both a systems of bromine in carbon tetrachloride anda cold, dilute, neutral permanganate solution (the Baeyer test). Bothtests are easily brought out; in one, a red shade disappears, and also in the other, a purple shade disappears and also is changed by brown manganese dioxide.
See even if it is in enhancement of Br₂ in CCl4 it gives red color or no ,It is a test to view the presence of the twin bond and also you can shot Lucas check on the alcohol
In a decent university dearteassociazione.org lab you could shot treatment with ozone, followed by triphenyl phosphine or reduction through zinc / acetic acid and then vapor distillation. The octene will type formaldehyde and heptanal when the octanol should do nothing.
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